Question

Flourine reacts with uranium to produce uranium hexafluoride, UF, as represented by this equation U(s) + 3F,(g) UF.(g) If no. of fluorine molecules are required to produce 7.04 mg of uranium hexafluoride, UF6, excess of uranium is y =10^19 then value of y ?​

Answer 1

Answer:

7.04 mg of uranium hexafluoride corresponds to

1000×352

7.04

=2×10

−5

moles or 2×10

−5

×6.023×10

23

=1.2×10

19

molecules.

The number of fluorine molecules required is 3×1.2×10

19

=3.6×10

19