Question

flow of current through a resistance is i=2√2sin 100 πt ampere.the rate of heat produced in the resistance 400 j/s then what is the value of the resistance?​

Answer 1

let 100πt=X

dx/dt=100π

dt=dx/100π

I=2√2sinx

400=8sin²100πR*1[since time is 1 second]

50=0*R

R=∞ Ω