Question

flow rate in a rectangular channel is 50ft^3/s and the width of the channel is 5 ft calculate the critical depth

Answer 1

Explanation:

Answer: normal depth = 1.02 m. (b) Geometry: trapezoidal cross-section with base width b, surface width �� + 2 × (2ℎ) and two sloping side lengths √ℎ2 + (2ℎ)2 = ℎ√5.

Answer 2

The critical depth of the channel is 2.54ft.

Given:-

The flow rate in a rectangular channel = 50ft³/sec

Width of the channel = 5ft (diameter)

To Find:-

The critical depth of the channel.

Solution:-

We can simply calculate the critical depth of the channel by using the following procedure.

As

The flow rate in a rectangular channel (v) = 50ft³/s

Width of the channel (d) = 5ft (diameter)

Radius of the channel (r) = 5/2ft

The critical depth of the channel (h) =?

According to the formula of volume of cylinder,

$v = \pi {r}^{2} h$

$50= \frac{22}{7} \times \frac{ {5}^{2} }{ {2}^{2} } \times h$

$50 = 3.14 \times \frac{25}{4} \times h$

$h = \frac{50 \times 4}{25 \times 3.14}$

$h = \frac{2 \times 4}{3.14}$

$h = \frac{8}{3.14}$

$h = 2.54ft$

Hence, The critical depth of the channel is 2.54ft.

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