Question

flowering plants/Non flowering plants

A tree/ A Shrub​

Answer 1

aa tree that is alright answer

Answer 2

Answer:

$\bf \huge \underline{ \orange{Required \: Answer : }}RequiredAnswer:</p><p></p><p>Given secΘ = 10/9 , calculate all other trigonometric ratios.</p><p></p><p>\bf \huge \underline{ \orange{answer : }}answer:</p><p></p><p>\begin{gathered}\begin{gathered}\sf{sec \: \theta = \frac{hyptenuse}{adjecent} = \frac{10}{9} } \\ \\\end{gathered}\end{gathered}secθ=adjecenthyptenuse=910</p><p></p><p>\bf{we \: will \: find \:the \: oppsite \: side }wewillfindtheoppsiteside</p><p></p><p>\begin{gathered}\begin{gathered}\to \tt{according \: to \: the \: attached \: diagram } \\\end{gathered}\end{gathered}→accordingtotheattacheddiagram</p><p></p><p>AB² + BC²=AC²</p><p></p><p>➜ AB² = AC² - BC²</p><p></p><p>➜ AB² = 10² - 9²</p><p></p><p>➜ AB² = 100 - 81</p><p></p><p>➜ AB² = 27</p><p></p><p>∴ AB = √27</p><p></p><p>\sf \small{all \: other \: trigonometric \: ratios \:are \: as \: follows : }allothertrigonometricratiosareasfollows:</p><p></p><p>\begin{gathered}\begin{gathered}\to \tt{sin \theta = \frac{opposite}{hypotenuse} = \frac{ \sqrt{27} }{10} } \\ \\ \to \tt{cos \ theta = \frac{adjecent}{hypotenuse} = \frac{9}{10} } \\ \\ \to \tt{tan \theta = \frac{opposite}{adjecent} = \frac{ \sqrt{27} }{9} } \\ \\ \to \tt{cot \theta = \frac{adjecent}{opposite} = \frac{9}{ \sqrt{27} } } \\ \\ \to \tt{cosec \theta = \frac{hypotenuse}{opposite} = \frac{10}{ \sqrt{27} } }\end{gathered}\end{gathered}→sinθ=hypotenuseopposite=1027→cos theta=hypotenuseadjecent=109→tanθ=adjecentopposite=927→cotθ=oppositeadjecent=279→cosecθ=oppositehypotenuse=2710</p><p></p><p>$

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