Fluid Mechanics (UPTU)
Properties of Fluids
Calculate the specific weight. specific mass, specific volume and specific gravity of
liquid having a volume of 6 m and weight of 44 KN
(Ans. : p = 747.5kg/m Sp. vol 0.00134m/kg, S 0.747)
Answers
Answer:
Fluid Mechanics (UPTU) Properties of Fluids Calculate the specific weight. specific mass, specific volume and specific gravity of liquid having a volume of 6 m and weight of 44 KN (Ans. : p = 747.5kg/m Sp. vol 0.00134m/kg, S 0.747). 1. See answer. Add answer. Log in to add comment. gauravkumar01135 ...
Explanation:
Answer:
specific weight:7333.34, specific mass=747.54
specific vol.=1.34*10³ sp gravity:0.747
Explanation:
solution:
Given
weight:44kn=44000
volume=6m³
mass(m)=44000/9.81=4489.79
now,
specific mass(mass density)=mass/volume
=4489.79/6
=747.54
specific weight (weight density)=weight/volume
= 44000/6
=7333.34
sp. volume=volume/mass
6/=4489.79
=1.34*10³
sp gravity= mass or weight density of fluid/mass or weight
density of water at 4°C
= 747.54/1000
=0.74754