Question

fluorescent lamp of length 1 m is placed horizontally at a depth of 1.2 m below a ceiling. a plane mirror of length .6 m placed below the lamp parallel to and symmetric to the lamp at a distance 2.4 m from it.find the length in meters of the reflected patch of light on the ceiling.


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Answer 1

Hello

Let CD be the fluorescent lamp placed below the ceiling at a depth of 1.2 m.
Let AB be the plane mirror placed below the lamp and PQ be the reflected patch on the ceiling.
By symmetry of triangles, MN=0.2m
PE=1m and QF=1m
Therefore, PQ=1+1+1=3m.

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Answer 2

Understand the figure.....1st