Fluorine does not exhibit any positive oxidation state why
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Fluorine is relatively smaller in size and is the element with high electro-negative property in periodic table.
It also has very high positive ionization enthalpy.
For fluorine to exhibit any positive oxidation state it has to be bonded to a negative element even higher than it which is not possible, thus fluorine does not exhibit any positive oxidation state.
It also has very high positive ionization enthalpy.
For fluorine to exhibit any positive oxidation state it has to be bonded to a negative element even higher than it which is not possible, thus fluorine does not exhibit any positive oxidation state.
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Answer: Yes it doesn't, but it does form positive oxidation state in one exceptional case, which is while forming oxo-acid!
Explanation: Fluorine doesn't form positive oxidation States for,it is REALLY SMALLER IN SIZE(absence of d-orbitals) , IT IS THE MOST ELECTRONEGATIVE ATOM AND HAS HIGH OXIDIZING POWER!!
But when fluorine is forming an oxo-acid , which is " HOF " , it shows +1 oxidation state! Cause, in order to make the whole compound charge zero! And we know that fluorine is more electronegative than oxygen, but due to the above reason, it shows +1 oxidation state! And flourine forms only one oxo-acid unlike other elements of group 17 , die to the absence of d-orbitals!!
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