Chemistry, asked by Abjalkhan3536, 8 months ago

Fluorine does not exhibit any positive oxidation state. Why? [Delhi 2013]

Answers

Answered by AbdJr10
3

Answer:

Fluorine is relatively smaller in size and is element with high electronegative property in periodic table .

for fluorine to exibit any positive oxidation state it has to be bounded to negative element even higher than it which is not possible, thus fluorine doesn't exibit positive oxidation state.

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Answered by sp208
0

Explanation:

Solution :

Electronic configuration of F is

(1s^2)(2s^2)(2p^5), F has only one unpair electorn. As F is the highest electronegative element, the possibility of sharing its electron with more electronegative element than itself is not there, hence it cannot show an oxidation state of +1 further, due to absence of d-orbitals in its valence shell, the paired electrons present in 2s or 2p electrons cannot be unpaired, hence F does not shown +3, +5 or +7 oxidation state too. Thus, fluorine does not exhibt any positive oxidation state.

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