Question

fnd the twenty fifth term of AP -5,-5/2,0,5/2​

Answer 1

Answer:

Add common difference to the previous term of AP

Answer 2

Answer:

given ;                                                                                                                    $\\ t_{1} = -5\\ t_{2}=\frac{-5}{2} \\... .\\ ..\\ \\ a = -5\\ \\ d = t_{2} - t_{1} \\ \\ d = \frac{-5}{2} +5\\ \\ d = \frac{-5+10}{2} \\ \\ d = \frac{5}{2}$

formula:$t_{n} = a +(n-1) d$$\\ \\ t_{25} = a + (25-1) d\\ \\ t_{25} = -5 + 24 * \frac{5}{2} \\ \\ t_{25} = -5 + 12*5\\ \\ t_{25} = -5+60\\ \\ t_{25} = 55$

t = 55 is the answer