Question

fnd the zeroes of the polynomial x*2-1 who will answer this I will mark brainliest ​

Answer 1

Step-by-step explanation:

x^2-1=0

x^2=1

x=√1

x=+or- 1

zeroes of x is 1,-1

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Answer 2

Step-by-step explanation:

We know that a^2-b^2 = (a+b) (a-b)

[Say] a = x^2 , b = 1

=> (x)^2 - (1)^2

=> (x+1) (x-1)

Either, (x+1) =0

=> x = -1

Or, (x-1) = 0

=> x = 1

Hence, Zeros of x^2-1 are 1,-1

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