Question

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Answer 1

Step-by-step explanation:

[1+cotA-CosecA]*[1+tanA+secA]

= 1 + tanA + secA + cotA + 1 + cosecA - (1/sinA) - (1/cosA) - secAcosecA

= 1 + tanA + secA + cotA + 1 + cosecA - cosecA - secA - secAcosecA

= 2 + tanA + cotA - secAcosecA

= 2 + [(sin^2A + cos^2A)/(sinAcosA)] - secAcosecA

= 2 + 1/(sinAcosA) - secAcosecA

= 2 + secAcosecA - secAcosecA

= 2

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Answer 2

Answer:

L. H. S

(1 + cos/sin - 1/sin) (1+ sin/cos + 1/ cos)

((sin + cos - 1)/sin) ((cos + sin + 1)/cos)

(sincos + sin^2 + sin + cos^2+ sincos +cos-cos -sin -1)/sincos

(2sincos + 1)/sincos

1+1

2

hence proved

L. H. S=R.H.S

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