Question

Focal length of a convex lens is 10cm. An object is at a distance of 8cm from pole of the lens. Now object moves by 4cm away from the lens. Find change in position of the image

Answer 1

Explanation:





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Question



An object is placed at a distance of 10cm from a convex lens of focal length 20cm. Find the position and nature of the image.

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Solution



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Given:u=−10cm               f=20cm        (convex lens)

To find: v and image's nature.

Solution: From lens formula

v1−u1=f1

v1+101=201

v1=20−1

v=−20cm

And magnification = uv=2

Hence image formed is virtual, erect and magnified two times.

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