focal length of a convex lens is 15 cm . where should an object be placed so that real and three times larger image is formed ?
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focal length = f = 15cm
Height of image (hi) = 3 x height of object (hi)
q = 3p (where q is image distance and p is object distace) ; As hi/ho = q/p
p = ??
1/f = 1/p + 1/q (formula)
1/15 = 1/p + 1/3p
1/15 = 4/3p
p = 15(4)/3
p = 20cm
Result: object distance is 20cm from the lens.
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