Physics, asked by ssk1395, 11 months ago

focal length of a convex mirror is 10 centimetre an object is kept at 20 cm from the pole of mirror. find the position of image​

Answers

Answered by Anonymous
18

\huge\underline\blue{\sf Answer:}

\red{\boxed{\sf Position\:of\:image(v)=+6.6cm }}

\huge\underline\blue{\sf Solution:}

\large\underline\pink{\sf Given: }

  • Focal lenght of mirror (f) = 10cm

  • Object kept at distance (u) = -20cm

\large\underline\pink{\sf To\:Find: }

  • Position of image (v) = ?

━━━━━━━━━━━━━━━━━━━━━━━━━━

According to Mirror Formula

\large{\boxed{\sf  \frac{1}{f}=\frac{1}{v}+\frac{1}{u}}}

\large\implies{\sf \frac{1}{10}=\frac{1}{v}+\frac{1}{-20}}

\large\implies{\sf \frac{1}{10}=\frac{1}{v}-\frac{1}{20}}

\large\implies{\sf \frac{1}{v}=\frac{1}{10}+\frac{1}{20} }

\large\implies{\sf \frac{1}{v}=\frac{20+10}{10×20} }

\large\implies{\sf v=\frac{200}{30} }

\large\implies{\sf v=+6.6cm}

\red{\boxed{\sf Position\:of\:image(v)=+6.6cm }}

______________________________________

  • Image is formed between pole and focus

  • Image is formed behind the mirror

  • Image is virtual and erect .

  • Size of image is small.
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Answered by Shreya091
135

\huge{\mathfrak{\underline{\pink{Answer:-}}}}

\large\star{\bf{\underline{\underline{Given:-}}}}

\large\sf\ focal \: length(f)= +10cm

\large\sf\ Object\: distance(u)= -20cm

\large\star{\bf{\underline{\underline{To \: find:-}}}}

\large\sf\ Image \: distance (v)=?

\large\star{\bf{\underline{\underline{ Mirror\: Formula \: used:-}}}}

\large\orange{\boxed{\sf\frac{1}{f}= \frac{1}{v} + \frac {1}{u} }}

\large\star{\bf{\underline{\underline{Solution:-}}}}

°Constitute the values given in formula ;

So,

\large\to\sf\frac {1}{f}= \frac {1}{v} + \frac {1}{u} \\ \\ \large\to\sf\frac {1}{10} = \frac {1}{v} + \frac {1}{-20} \\ \\ \large\to\sf\frac {1}{v}= \frac {1}{10} + \frac {1}{20} \\ \\ \large\to\sf\frac{1}{v}=\frac {20+10}{10 \times\ 20} \\ \\ \large\to\sf\large\frac{1}{v}= \frac {30}{200}\\\ \\ \large\to\sf\ v= \frac {200}{30} \\ \\ \large\to\bf\ v=+0.66cm

_____________

\large{\bf{\underline{\underline{Nature \: of \: image :-}}}}

Virtual and erect.

Diminished .

Behind the mirror.

\mathbb\red{Thanks...}

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