Focal length of convex lens is 2cm of refractive index 1.5 .focal length when it immersed in liquid of refractive index 1.25 will be
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When in air : P1 = (n-1) (X), where X = (1/R1- 1/R2)
When in water : P2 = (n-1.33) (X)/ 1.33
Solving them we get, P1/P2 = 1.33 (n-1) / (n-1.33)
P1 = 1/20 cm = 5 diopters
Assuming n = 1.5 (glass lens), P2 = 1.28 (approx).
Focal length = 78 cm
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Explanation:
Focal length of the glass lens in air is 2c.m. It's focal length when immersed in water would be???
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