Question

Focal length of objective and eye piece of telescope is 200 and 10 cm the lenth of telescope for maximum magnification

Answer 1

Answer:

is given that,

Focal length of eye- piece fe = 4 cm

Focal length of object is fo = 200 cm

Least distance of distinct vision is d = 25 cm

So, magnifying power of microscope is

M=

f

e

−f

0

(1+

d

f

e

)

M=

4

−200

(1+

25

4

-58