Question

Focal lenth 30 cm and object distance 60 cm ina convex mirror claculate position of image

Answer 1

Answer:

$given :$

$focal \: \: length \: = \: 30cm$

$object \: \: distance \: = \: - 60 \: cm$

$according \: \: to \: \: mirror \: \: formula$

$\frac{1}{v} \: + \frac{1}{u} \: = \: \frac{1}{f}$

$substitute \: \: values \: \: of \: \: u \: \: and \: f$

$that \: \: \: is$

$\frac{1}{v } \: + \frac{1}{ - 60} \: = \frac{1}{30}$

$so \: \: \frac{1}{v} \: \: = \: \: \frac{1}{30} \: \: + \: \: \frac{1}{60}$

$\frac{1}{v} \: = \: \frac{1}{20}$

$so \: \: \: v = 20 \: \: cm$

$we \: \: took \: \: f \: \: positive \: \: as \: \: \\ \: we \: \: are \: \: given \: \: convex \: \: mirror$