Question

FOLLOW ME ON INSTA @__princely___and the question is
If
the radius of the Gaussian surface enclosing a charge is halved, how does the electric flux through the Gaussian surface change ?​

Answer 1

answer..

If reducing the radius of the Gauss surface doesn't discontinue or break the surface and encloses the whole charge as it initially was, then the net electric flux through the surface remains constant. That is because the flux through an enclosed surface is the dot product of electric field times the enclosed area .

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Answer 2

Answer:

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Explanation:

When dipole moment vector is parallel to electric field vector.