Question

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question :

$3 {x}^{2} - 2 \sqrt{6} + 2 = 0$
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Answer 1

Answer:

3 x^{2} -2√6x+2=0

3 x^{2} -√6x-√6x+2=0

√3 x^{2} *√3 x^{2} -√3x*√2x-√3x*√2x+√2*√2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-√2)(√3x-√2)=0

x=√2/√3

Therefore the equation has two equal roots; √2/√3