Question

following algebraic expression find the common factors 4xyz , 12yz
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Answer 1

Answer:

4yz

Step-by-step explanation:

4xyz, 12yz

=4(xyz, 3yz)

=4yz(x, 3)

Therefore, 4yz are common factor of 4xyz and 12yz

Answer 2

Answer:

4yz

Step-by-step explanation:

As 4xy = 2 × 2 × x × y × z

And 12yz = 2 × 2 × 3 × y × z

As we see that 2 × 2 × y × z is common in both the terms.

Hence the answer is 2×2×y×z = 4yz