Question

Following are the observation of throwing a dice 15 times

5, 3, 4, 1, 6, 2, 2, 4, 3, 2, 1, 5, 1, 6, 2

Find the mean, mode and median of this data.​

Answer 1

Answer:

• Mean = $\sf\dfrac{47}{15}$
• Mode = 2
• Median = 3

Step-by-step explanation:

Given,

Series :-

5 , 3 , 4 , 1 , 6 , 2 , 2 , 4 , 3 , 2 , 1 , 5 , 1 , 6 , 2.

To Find :-

• Mean
• Mode
• Median

Solution :

$Mean= \frac{Sum\: of\: the \: observations}{Number\: of\: the\: observations}$

Sum of the Observations = 5 + 3 + 4 + 1 + 6 + 2 + 2 + 4 + 3 + 2 + 1 + 5 + 1 + 6 + 2

= 47

Number of the Observations = 15

$Mean = \frac{47}{15}$

Mode = Frequently repeated number in the series.

i.e

2 is the Mode because it repeated four times

Median = middle term of the series when series are in Ascending order.

Arranging series in Ascending order :-

1 , 1 , 1 , 2 , 2 , 2 , 2 , 3 , 3 , 4 , 4 , 5 , 5 , 6 , 6.

Middle term = Median = 3

$[tex]\sf\therefore Mean , Mode , Median = \frac{47}{15} , 2 , 3$

Answer 2

Given :

Observation in thr throwing a dice into 15 times

5, 3, 4, 1, 6, 2, 2, 4, 3, 2, 1, 5, 1, 6, 2

To Find :

Mean, mode and median of the data .

Solution :

5, 3, 4, 1, 6, 2, 2, 4, 3, 2, 1, 5, 1, 6, 2

Arranging all data in order

111 2 2 2 2 3 3 4 4 5 5 6 6

Now , there are total 15 datas

Hence, 8th data will be median

Hence, 3 is the median

2 has maximum frequency as 4

So , 2 is the MODE

Mean = (1+ 1+1+2 + 2 + 2 + 2+ 3+3 +4 + 4 + 5 + 5 + 6 + 6)/15

= 47/15

= 3.13

The final answer of the question is !!

Mean is 3.13