Question

Following are the wages of 8 workers in rupees:50,62,40,70,45,56,32 ,45 If one of the workers is selected at random,what is the probability that his wages would be lower than the average wage?




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Answer 1

Answer:

$\frac{1}{2}$

Step-by-step explanation:

We are given that the wages of 8 workers in rupees:

50,62,40,70,45,56,32 and 45

Average wage=$\frac{Sum\;of wages}{total\;number\;of\;workers}$

Average wage=$\frac{50+62+40+70+45+56+32+45}{8}=50$

We have to find the probability that his wages would be lower than the average wage.

Wages of worker less than average wage=45,45,40,32

Total number of worker=8

Number of workers whose wages are less than average wages=4

Probability,$P(E)=\frac{number\;favorable\;cases}{total\;number\;of\;cases}$

Therefore, the probability that his wages would be lower than the average wage=$\frac{4}{8}=\frac{1}{2}$

Answer:$\frac{1}{2}$