Question

Following data is given for a 360 hydrodynamic bearing: journal diameter = 100mm,Bearing length •100 mm, Radial load = 50kN Journal speed = 1440 rpm, Viscority of lubricant =16cP. Determine film thickness,
1) minimal film thickness , 2) coefficient of friction ,3) power lost in friction​

Answer 1

Answer:

power lost in friction

Answer 2

(1) minimal film thickness = 0.02 mm

(2) coefficient of friction = 0.00322

(3) power lost in friction = 0.012 W

Given,

journal diameter (d) = 100mm

bearing length (l) = 100mm

radial load (W) = 50kN

journal speed (n) = 1440rpm

viscosity of lubricant (v) = 16cP

radial clearance (c) = 0.05mm

We know that,

(1) minimal film thickness is given by,

$h_o=0.4c$

⇒ $h_o=0.4(0.05)$

⇒ $h_o=0.02mm$

(2) coefficient of friction is given as,

$f=3.22(\frac{c}{r})$

⇒ $f=3.22(\frac{0.05}{50})$

⇒ $f=0.00322$

(3) power lost in friction is given as,

$(kW)_f=\frac{2 \pi nfWr}{10^{8}}$

⇒ $(kW)_f=\frac{2 \pi (\frac{1440}{60})(0.00322)(50)(1000)(50) }{10^{8}}$

⇒ $(kW)_f=0.012W$

Learn more about hydrodynamic bearing

https://brainly.in/question/8633014

Hydrodynamic bearing

https://brainly.in/question/12339919

#SPJ2