Question

following examples.
Ex. (1) In A ABC, ZC is an acute angle, seg AD I seg BC. Prove that:
AB? = BC + AC? - 2BC x DC
In the given figure let AB = C, AC = b. AD = p. BC = a, DC = X
... BD = a-X
In A ADB , by Pythagoras theorem
c? = (a-x)+|
C = 6 - 2ax + x +
In A ADC, by Pythagoras theorem
a-x DX
6² = p² +
Fig. 2.23
p² = 6² - um (11)
Substituting value of p' from (II) in (I),
c= 6 - 2x + x + b -
c = a + b² - 2ax
.. ABP = BC + AC-2BCX DC​

Answer 1

Answer:

ABP=BC+2BCX DC

ABP=ABP