Question

Following figure shows the only two forces X and Y acting on a box. Force Y Force X Left Right 59 N 45 N 0 What is the net force acting on the box? () In which direction will the box move? (iii) What can be done to achieve an equilibrium position for the box?​

Answer 1

Answer:

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Explanation:

send a clear pic once more

Answer 2

Explanation:

Given:

• From both the sides of the box, forces are exerted to push the box.  
• From the left side, the box is being pushed to the right side with a force Y of $59N$.  
• From the right side, the box is being pushed to the left side with a force X of $45N$.  

To find: Direction of motion of box, equilibrium condition

Calculation:

The net force acting on the box is the sum total of all the individual forces by taking their direction into account.  

So, net force F is:

$F=X+Y$  

Let the Direction towards right side be positive, so

$Y=59N\\X=-45N$  

Therefore,

$F=(+59)+(-45)=14N$  

So, net force is unbalanced and non-zero will be  in the right direction.  

The motion of direction for the box is towards the right side.  

For achieving equilibrium, a force of   should be exerted from the right side towards the left side. That will cause a balance force and the net force will be zero.  

Answer:

(a) The motion of direction for the box is towards the right side.  

(b) For achieving equilibrium, a force of   should be exerted from the right side towards the left side. That will cause a balance force and the net force will be zero.