Question

Following figure shows two processes A and B for a gas. If ∆QA and ∆QB are the amount of heat absorbed by the system in two cases, and ∆UA and ∆UB are changes in internal energies, respectively, then:
(A) ∆QA = ∆QB; ∆UA = ∆UB
(B) ∆QA > ∆QB; ∆UA = ∆UB
(C) ∆QA < ∆QB; ∆UA < ∆UB
(D) ∆QA > ∆QB; ∆UA > ∆UB

Answer 1

Answer:

(B). will be correct answers

Heat is a path dependant process .

and in process 1st volume change is more than process 2nd.

Internal is state function and in both process initial and final state is same .

so change in internal energy will be zero.

Explanation:

hope the answer will help you

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