Question

Following limiting molar conductivities are given as
 o m  H 2 SO 4   x Scm 2 mol  1
 o m  K 2 SO 4   yScm 2 mol  1
 o m  CH 3 COOK   zScm 2 mol  1
 0 m  in S cm 2 mol  1  for CH 3 COOH will be

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Answer 1

Answer:

d is correct answer

Explanation:

according to kohlrausch law