Question

Following liquids with the given densities are taken in separate beakers:

1. Honey (approx. 1.4 g/cm”)
2. Glycerine (approx. 1.3 g/cm3)
3. Water (approx. 1 g/cm3)​

Answer 1

Answer:

−ms

dt

dT

=eσA(T

4

−T

0

4

)

−

dt

dT

=

ms

eσA

(T

4

−T

0

4

)

−

dt

dT

=

ms

4eσAT

0

3

(△T)

T=T

0

+(T

i

−T

0

)e

−kt

where k=

ms

4eσAT

0

3

k=

ρvs

4eσAT

0

3

∣

∣

∣

∣

∣

dt

dT

∣

∣

∣

∣

∣

∝k

∴

∣

∣

∣

∣

∣

dt

dT

∣

∣

∣

∣

∣

∝

ρs

1

ρ

A

S

A

=2000×8×10

2

=16×10

5

ρ

B

S

B

=4000×10

3

=4×10

6

ρ

A

S

A

<ρ

B

S

B

∣

∣

∣

∣

∣

dt

dT

∣

∣

∣

∣

∣

A

>

∣

∣

∣

∣

∣

dt

dT

∣

∣

∣

∣

∣

B

.

Answer 2

Answer:

3) Water (approx.1g/cm3).