Question

Following observations obtained in the boy's calorimeter equipment find the GCV and NCV of the fuel.
Volume of gas Burnt = 0.08m^3
Mass of cooling water used= 29.5 kg
Temperature of circulating water = 9.1
Mass of stem condensed point = 0.04 kg
​

Answer 1

Explanation:

Calculate a) Gross calorific value, moist basis b) Net calorific value, dry basis c) Net calorific value, moist basis d) Gross calorific value, dry basis using Dulong formula. = 32060.2 KJ/Kg NCV = GCV – 24.44(9×%H + %M) = 30630.26 KJ/Kg Thus NCV = 0.955 times GCV in this case.

$\huge \pink{H} \orange {e} \red {a} \green {r} \blue {t} \orange {S} \pink {l} \red {a} \green {y} \blue {e} \orange {r}$ $\huge {⚘}$

Answer 2

Answer:

Calculate a) Gross calorific value, moist basis b) Net calorific value, dry basis c) Net calorific value, moist basis d) Gross calorific value, dry basis using Dulong formula. = 32060.2 KJ/Kg NCV = GCV – 24.44(9×%H + %M) = 30630.26 KJ/Kg Thus NCV = 0.955 times GCV in this case.

Explanation:

Please mark me as the brainliest and drop some thanks