Question

Following questionNo.5 are multiple choice question carrying one mark (1x1=1)

5. In electrolysis of NaCl when Pt electrode is taken then H2 is liberated at cathode

while with Hg cathode, it forms sodium amalgam

a) Hg is more inert than Pt

b) More voltage is required to reduce H+

at Hg than at Pt

c) Na is dissolved in Hg while it does not dissolve in Pt

d) Conc. of H+

ions is larger when Pt electrode is taken​

Answer 1

Answer:

However, due to over-voltage for the liberation of H2(g) at Hg electrode, the H+ ions arc not discharged at Hg cathode. Thus, Na+ ions are discharged at cathode (in perference of H+ ions) yielding Na metal, which dissolves in Hg to form sodium amalgam.

Explanation:

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