Question

following sets of three forces act on a body.whose resultant cannot be zero?
a.10,10,10
b.10,10,20
c. 10,20,23
d.10,20,40

Answer 1

Answer:  The correct option is (d)

Explanation:

Given that,

let us considered three forces in equilibrium and represents three sides of a triangle a,b and c.

We know that,

In the triangle, addition of the two sides is greater than the third side then the resultant might be zero but when addition of the two sides is less than the third side then the resultant can not zero.

Therefore,  the resultant force will not be zero

$(a+b)<c$

(a). a = 10, b = 10, c = 10

The resultant force is  

$(a+b)<c$

$(20)<10$

The resultant force is zero.

(b).  a = 10, b = 10, c = 20

The resultant force is  

$(a+b)<c$

$(20)<20$

The resultant force is zero.

(c). a = 10, b = 20, c = 23

The resultant force is  

$(a+b)<c$

$(30)<23$

The resultant force is zero.

(d). a = 10, b = 20, c = 40

The resultant force is  

$(a+b)<c$

$(30)<40$

The resultant force is not zero.

Hence, The correct option is (d).

Answer 2

Explanation:

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