fond the zeroes of root
![3x {}^{2} + 10x + 7 \sqrt{3} 3x {}^{2} + 10x + 7 \sqrt{3}](https://tex.z-dn.net/?f=3x+%7B%7D%5E%7B2%7D+%2B+10x+%2B+7+%5Csqrt%7B3%7D+)
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Answers
Answered by
55
Correction: Polynomial is √3x² + 10x + 7√3
Solution:
The given Polynomial is √3x² + 10x + 7√3
f(x)= √3x² + 10x + 7√3 = 0
= √3x² + 3x + 7x + 7√3 = 0
=√3x (x + √3) + 7(x+ √3) = 0
f(x) = (√3x + 7)(x + √3)
Zeroes of Polynomial : -7√3 & -√3 .
Answered by
56
Answer:-
Step-by-step explanation:
Question Should be return like this Polynomial is √3x² + 10x + 7√3 = 0
Given:-
√3x² + 10x + 7√3 = 0
Solution:-
⇒ √3x² + 10x + 7√3 = 0
⇒ √3x² + 7x + 3x + 7√3 = 0
⇒ x(√3x + 7) + √3(√3x + 7) = 0
⇒ (√3x + 7) (x + √3) = 0
⇒ √3x + 7 = 0
⇒ √3x = -7
⇒ x = -7/√3
⇒ x + √3 = 0
⇒ x = -√3
Therefore, -7/√3 and -√3 are zeroes of the polynomial.
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