Math, asked by pixie03, 1 year ago

Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. Calculate the height of the point on the wall where the top of the ladder reaches.

Answers

Answered by Arindeep
0

Answer:

height of the wall till the top of ladder reaches= 8m

Step-by-step explanation:

length of ladder= 10m

base= 6m

height of the wall till the top of ladder reaches= let it be x .

by Pythagoras theorem

10²= x²+6²

100= x²+36

100-36= x²

64=x²

√64=x

x= 8m

Answered by Anonymous
2

Let PR be the ladder and QR be the vertical wall.

Length of the ladder PR = 10 m

PQ = 6 m

Let height of the wall, QR = h

According to Pythagoras theorem,

PR2 = PQ2+QR2

102 = 62+QR2

100 = 36+QR2

QR2 = 100-36

QR2 = 64

Taking square root on both sides,

QR = 8

Hence the height of the wall where the top of the ladder reaches is 8 m.

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