Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. Calculate the height of the point on the wall where the top of the ladder reaches.
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Answered by
0
Answer:
height of the wall till the top of ladder reaches= 8m
Step-by-step explanation:
length of ladder= 10m
base= 6m
height of the wall till the top of ladder reaches= let it be x .
by Pythagoras theorem
10²= x²+6²
100= x²+36
100-36= x²
64=x²
√64=x
x= 8m
Answered by
2
Let PR be the ladder and QR be the vertical wall.
Length of the ladder PR = 10 m
PQ = 6 m
Let height of the wall, QR = h
According to Pythagoras theorem,
PR2 = PQ2+QR2
102 = 62+QR2
100 = 36+QR2
QR2 = 100-36
QR2 = 64
Taking square root on both sides,
QR = 8
Hence the height of the wall where the top of the ladder reaches is 8 m.
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