Football is kicked vertically upward with the velocity of 29.4 metre per second what will be its velocity after 1 second?
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Explanation:
Initial Velocity, U = 29.4 m/s
Final Velocity, V = 0
Thus height obtained by ball, S = (V^2 - U^2)/2a
Here a = g as the ball has a deceleration of g
S = 0 - (29.4)^2/2*9.8
S = 864.36/19.6
S = 44.1 m
Thus Velocity after 1 second, V1
S = V1T - 1/2aT^2
here T = 1
Thus,
44.1 = V1 - 1/2*9.8
Thus, V1 = 44.1 + 4.9
Thus V1 = 49 m/s
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