for 10 points give me the answere plz
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Step-by-step explanation:
x+y+z=0
we know
x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
putting x+y+z=0
x³+y³+z³-3xyz=(0)(x²+y²+z²-xy-yz-zx)
x³+y³+z³-3xyz=0
x³+y³+z³=3xyz
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