Math, asked by utkarshgameing, 10 months ago

for 10 points give me the answere plz ​

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Answered by sandy1816
1

Step-by-step explanation:

x+y+z=0

we know

x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)

putting x+y+z=0

x³+y³+z³-3xyz=(0)(x²+y²+z²-xy-yz-zx)

x³+y³+z³-3xyz=0

x³+y³+z³=3xyz

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