Question

For 20 points,

3x-5y=4
2y+7=9x.
Solve the given pair of linear equations.

Answer 1

hey mate here's your answer

given equations are 3x-5y=4-----(1) and 9x-2y=7------(2)

multiplying eqn (1) with 3

9x-15y=12

9x- 2y =7

- + -

_________

-13y=5

y=-5/13

adding the value of y in eqn (1),

x=43/39

Answer 2

Answer:

$x=\frac{9}{13}$ and $y=\frac{-5}{13}$

Step-by-step explanation:

Given two linear equations,

$3x-5y=4$

$2y+7=9x$

We have to solve the above two equations.

we solve above two by substitution method

Take first equation

$3x-5y=4$  ⇒ $3x=4+5y$

Now, substitute the value of 3x in second, we get

$2y+7=9x$

⇒ $3(3x)=2y+7$

Substituting 3x=4+5y

$3(4+5y)=2y+7$

⇒ $12+15y=2y+7$ ⇒ $15y-2y=7-12$

                          ⇒ $13y=-5$

                          ⇒ $y=\frac{-5}{13}$

gives $9x=2y+7=2(\frac{-5}{13})+7$

⇒ $9x=\frac{81}{13}$

⇒ $x=\frac{9}{13}$

Hence, $x=\frac{9}{13}$ and $y=\frac{-5}{13}$