Chemistry, asked by rthe3739, 6 months ago

For 200g CaCo3 . find (a)Mole (b)no of molecules (c)no of mole molecules (d)no of mole atom (e) no of atom

Answers

Answered by fenisebastian
1

ANSWER

ANSWERThe molecular weight of calcium carbonate is 100 g.

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole.

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole. One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole. One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N A

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole. One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N A

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole. One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N A atoms. Here, N

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole. One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N A atoms. Here, N A

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole. One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N A atoms. Here, N A

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole. One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N A atoms. Here, N A is the Avogadro number.

ANSWERThe molecular weight of calcium carbonate is 100 g. 10 g of calcium carbonate corresponds to 0.1 mole. One molecule of calcuim carbonate contains 5 atoms. Hence, 0.1 mole of calcium carbonate will contain 0.5N A atoms. Here, N A is the Avogadro number.Hope it helps you please add me to brainlist

Similar questions