Question

For 224 mL of So2 gas at Stp calculates
1. Moles
2. mass
3. No. of molecules​

Answer 1

Answer:

(A) 1 mole of a gas has 22.4 L of volume at STP.

Therefore, 224 ml (0.224 L) of SO2 at STP has 0.224 / 22.4 = 0.01 mole

Now,

1 mole of SO2 has 6.022 x 1023 molecules

Therefore, 0.01 mole of SO2 has 0.01 x 6.022 x 1023 = 6.022 x 1021 molecules.

I don't know others

Answer 2

Answer:

1) Number of moles for 224ml of SO₂ gas at STP is 0.01 mol.

2) Mass of SO₂ gas is 0.64g.

3) Number of molecules for 0.01 mol of gas is 6.022 × 10²¹ molecules.

Explanation:

Given,

Volume of SO₂ gas at STP, V= 224ml

Convert ml into L

• 1ml = 10⁻³ L
• 224 ml = 0.224 L

Here, STP is standard temperature and pressure, i.e., at 0° C temperature and 1 bar pressure.

1) Number of moles, n =?

As we know, the volume of an ideal gas at STP condition is 22.41 L.

So,

• 1 mole of gas at STP = 22.4 L
• $1 L = \frac{1}{22.4} mol$
• $0.224 L = \frac{0.224}{22.4} mol$  = 0.01 mol

Therefore, number of moles, n = 0.01 mol

2) Mass of SO₂ gas, m =?

• Molar mass of SO₂ = atomic mass of sulphur + 2 atomic mass of oxygen
• Molar mass of SO₂ = 32 + 2 × 16 = 64 g/mol

As we know,

• $n = \frac{m}{M}$

Here,

• n = number of moles of a gas
• m = mass of a gas
• M = molar mass of a gas

Therefore,

• $0.01 = \frac{m}{64}$
• m = 0.01 × 64 = 0.64g
• Mass of SO₂ gas = 0.64g

3) Number of molecules =?

• 1 mol = 6.022 × 10²³ molecules
• 0.01 mol = 0.01 × 6.022 × 10²³ = 6.022 × 10²¹ molecules
• Number of molecules = 6.022 × 10²¹ molecules

Hence, from the calculations we get,

Number of moles = 0.01 mol

Mass of SO₂ gas = 0.64g

Number of molecules = 6.022 × 10²¹ molecules.