For 25% decrease in temperature find percent decrease in volume
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PV=P′V′PV=P′V′ { initial condition = final condition; nRT=nRT′nRT=nRT′ }
V′=0.95V(V−(5∗V)/100)V′=0.95V(V−(5∗V)/100)
P′P=1.052P′P=1.052
Increase in Pressure =P′−PP×100=P′−PP×100
K=(1.052−1)×100K=5.2K=(1.052−1)×100K=5.2
Increase in pressure = 5.2%
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Anand Natarajan
Answered Jul 7, 2018
Let initial volume and pressure be V1 and P1 respectively.
Let final volume and pressure bee V2 and P2.
Using PV=nRT, if temperature is constant, then PV= constant.
=> P1V1 = P2V2
Given, final volume is 95% of initial volume.
=> V2 = 95V1/100
=> P1V1 = P2 * 95 V1/100
=> P1 = P2 * 95/100
=> P2 = P1 * 100/95 = 1.052631 P1
This roughly translates to an increase of 5.2631%
Therefore the pressure should be increased by 5.2631% approximately.
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Chandra Prakash, former Intern at TATA STEEL LTD. JAMSHEDPUR (2016-2017)
Updated Dec 2, 2016
Ideal gas equation (PV=mRT),
as temperature remains constant we can apply Boyle’s Law,
the law can be usefully expressed as P₁V₁ = P₂V₂.
V₂ =0.95 V₁ (as V₂ is 5% less than V₁)
P₁×V₁ = P₂×V₂
P₁×V₁ = P₂ (0.95×V₁)
P₂ = P₁/ 0.95
P₂ = 1.052 P₁


% Increase in pressure = 5.2
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Prasad Selvaraj, B. E Mechanical Engineering, Mepco Schlenk Engineering College, Sivakasi, Tamil Nadu, India (2019)
Answered Jun 21, 2018 · Author has 122answers and 69.1k answer views
For constant temperature, PV = constant.
P1V1=P2V2
P1V1=P2 x 0.95V1
P1 = 0.95P2
P2 = 1/0.95 x P1
P2 = 1.0526 x P1
Therefore, there will be an approximate increase of 5.26%.
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G.S Vignesh, Be Union Public Service Commission of India & Graduate Aptitude Test in Engineering, Mechanical Engineering...
Answered Jul 2, 2018
5% increase . the easiest way to solve is at constant temperature pressure is inversely proportional to volume or product of them is a constant. So...
TO READ THE FULL ANSWER
V′=0.95V(V−(5∗V)/100)V′=0.95V(V−(5∗V)/100)
P′P=1.052P′P=1.052
Increase in Pressure =P′−PP×100=P′−PP×100
K=(1.052−1)×100K=5.2K=(1.052−1)×100K=5.2
Increase in pressure = 5.2%
7.5k Views · View Upvoters
Your feedback is private.
Is this answer still relevant and up to date?
MORE ANSWERS BELOW. RELATED QUESTIONS
By what percentage should the pressure of a given mass of gas be increase so as to decrease it volume by 10% at a constant temperature?
6,000 Views
At constant temperature if pressure is increased by 1% what is the percentage decrease of the volume?
1,519 Views
How much should the pressure be increased in order to decrease the volume of a gas by 5% at a constant temperature?
379 Views
Why does the volume of a gas decrease as the pressure is increased at constant temperature?
1,218 Views
Why, at constant volume for a fixed number of moles of a gas, does the pressure of a gas increase with increase in temperature?
945 Views
OTHER ANSWERS

Anand Natarajan
Answered Jul 7, 2018
Let initial volume and pressure be V1 and P1 respectively.
Let final volume and pressure bee V2 and P2.
Using PV=nRT, if temperature is constant, then PV= constant.
=> P1V1 = P2V2
Given, final volume is 95% of initial volume.
=> V2 = 95V1/100
=> P1V1 = P2 * 95 V1/100
=> P1 = P2 * 95/100
=> P2 = P1 * 100/95 = 1.052631 P1
This roughly translates to an increase of 5.2631%
Therefore the pressure should be increased by 5.2631% approximately.
403 Views · View Upvoters
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Chandra Prakash, former Intern at TATA STEEL LTD. JAMSHEDPUR (2016-2017)
Updated Dec 2, 2016
Ideal gas equation (PV=mRT),
as temperature remains constant we can apply Boyle’s Law,
the law can be usefully expressed as P₁V₁ = P₂V₂.
V₂ =0.95 V₁ (as V₂ is 5% less than V₁)
P₁×V₁ = P₂×V₂
P₁×V₁ = P₂ (0.95×V₁)
P₂ = P₁/ 0.95
P₂ = 1.052 P₁


% Increase in pressure = 5.2
15.7k Views · View Upvoters

Prasad Selvaraj, B. E Mechanical Engineering, Mepco Schlenk Engineering College, Sivakasi, Tamil Nadu, India (2019)
Answered Jun 21, 2018 · Author has 122answers and 69.1k answer views
For constant temperature, PV = constant.
P1V1=P2V2
P1V1=P2 x 0.95V1
P1 = 0.95P2
P2 = 1/0.95 x P1
P2 = 1.0526 x P1
Therefore, there will be an approximate increase of 5.26%.
349 Views · View Upvoters

G.S Vignesh, Be Union Public Service Commission of India & Graduate Aptitude Test in Engineering, Mechanical Engineering...
Answered Jul 2, 2018
5% increase . the easiest way to solve is at constant temperature pressure is inversely proportional to volume or product of them is a constant. So...
TO READ THE FULL ANSWER
Answered by
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4³= 64
3³= 27
% decrease= 37/64×100= 57.81
3³= 27
% decrease= 37/64×100= 57.81
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