for √2x² – 5x + √2 = 0, find the value of the determinant
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Step-by-step explanation:
By Comparing √2x² -5x +√2 =0 with standard form of quadratic equation ax²+bx+c = 0 , we get. a=√2. b = -5. c = √2. Discriminant (Δ) = b²-4ac.
= (-5)²-4×√2×√2. = 25 - 4×2. = 25 - 8.
= 17. Therefore,
Discriminant = 17.
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By Comparing √2x² -5x +√2 =0 with standard form of quadratic equation ax²+bx+c = 0 , we get. a=√2. b = -5. c = √2. Discriminant (Δ) = b²-4ac.
= (-5)²-4×√2×√2. = 25 - 4×2. = 25 - 8.
= 17. Therefore,
Discriminant = 17.
Hope that helps you
Mark my answer as brainliest
Foll low me pls
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