Question

For 2y² - 5y +10 = 0 find the value of the discriminant.
50
−55
105
−65
​

Answer 1

Answer:

answer is -55 buddddy.hope it helped you

Answer 2

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Here is the answer

Here is the answerComparing the given Equation with ax^2 + bx + c = 0

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2 −4ac

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2 −4ac\bf{ = ( - 5) {}^{2} - 4 \times 2 \times 10}=(−5)

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2 −4ac\bf{ = ( - 5) {}^{2} - 4 \times 2 \times 10}=(−5) 2

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2 −4ac\bf{ = ( - 5) {}^{2} - 4 \times 2 \times 10}=(−5) 2 −4×2×10

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2 −4ac\bf{ = ( - 5) {}^{2} - 4 \times 2 \times 10}=(−5) 2 −4×2×10\bf{ = 25 - 80}=25−80

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2 −4ac\bf{ = ( - 5) {}^{2} - 4 \times 2 \times 10}=(−5) 2 −4×2×10\bf{ = 25 - 80}=25−80\bf{ = - 55}=−55

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2 −4ac\bf{ = ( - 5) {}^{2} - 4 \times 2 \times 10}=(−5) 2 −4×2×10\bf{ = 25 - 80}=25−80\bf{ = - 55}=−55Thus,

Here is the answerComparing the given Equation with ax^2 + bx + c = 0We get,a = 2b = -5c = 10Now,\bf{ \triangle = {b}^{2} - 4ac}△=b 2 −4ac\bf{ = ( - 5) {}^{2} - 4 \times 2 \times 10}=(−5) 2 −4×2×10\bf{ = 25 - 80}=25−80\bf{ = - 55}=−55Thus,The value of discriminant is -55.

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