Question

for 3 moles of monoatomic gas Cp/Cv is???

​

Answer 1

Answer:

As we know, C

v

for monoatomic gas is 3R/2 and for diatomic gas is 5R/2.

So for mixture, Cv =1x3/2 R+3x5/2xR÷4=9/4Rx9/2xR =9.2kal

MARK ME AS BRAINLEST!!

Answer 2

Given: 3 moles of monoatomic gas is present

To find: Cp/Cv of the gas

Explanation: Monatomic gas is a type of gas composed of particles (molecules) that consist of single atoms, such as helium or sodium vapour.

A monoatomic gas has 3 degrees of freedom(f).

The formula used for Cv is fR/2 where R is gas constant.

Here, Cv= 3R/2 (f= 3 for monoatomic gas)

Mayer' s formula states that, Cp= Cv+R

= 3R/2 + R

= 5R/2

Now, Cp= 5R/2 and Cv= 3R/2

Therefore, Cp/Cv = (5R/2) / (3R/2)

= 5/3

= 1.66

Therefore, for monoatomic gas Cp/Cv is 1.66