Question

for θ=30°, verify than cos θ = 1/√(1+tan^2 θ)​

Answer 1

Answer:

Lemme write,

Step-by-step explanation:

for θ = 30° ,

LHS,

cos30° = √3/2

RHS,

1/√( 1 + tan^2 30°)

= 1/√ ( 1 + (1/√3)^2)

= 1/√ (1 + 1/3)

= 1/ √ (4/3)

= (1/√4)*√3

= (1/2)*√3

= √3/2 = LHS (proved)

Answer 2

Answer:

L.H.S. cos30=square root3/2

R.H.S. 1/square root(1+tan^2☆)

1//sec☆

cos☆

cos30=square 3/2

L.H.S.=R.H.S proved