Question

For 3phase Delta connection,following relation is true
 A. IL=Iph 
B. IL=3Iph
 C. IL=√3Iph
 D. IL=2Iph ​

Answer 1

Answer:

option c that is line current is √3 times of phase current

Answer 2

Explanation:

In Delta, Vphase = VLine. Where as in Star Connection Vphase = VLine/sqrt(3).

Similarly

In Star, Iphase = ILine. Where as in Delta Connection Iphase = ILine/sqrt(3).

This is because Line Current in Delta is difference b/w two phase currents

i.e,

IR= IRY-IBR;

IY= IYB-IRY

IB = IBR-IYB

Where IR=IB-IY= ILine

IRY=IYB=IBR=Iphase

IR=Sqrt((IRY)^2+(IBR)^2+2*IRY*IBR*Cos(60));

and above equation becomes

ILine= Sqrt(Iphase^2+Iphase^2+2*Iphase*Iphase*Cos(60));

Hence

ILine = Sqrt(3) * Iphase. .

hope it's helps you.......