For √(3x^2 )+5x-2√3=0, discuss its nature of roots.
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To justify the nature of the roots of the above equation
Given,
The nature of the roots of a equation are determined by its discriminant,D
•If the discriminant is:
1. Greater than zero,D>0,has real and distinct roots
2. Equal to zero,D=0,has real and equal roots
3. Less than zero,D<0,has non real roots or imaginary roots
Comparing with ax²+bx+c=0,
a=√3,b=5 and c= -2√3
Discriminant,D=b²-4ac
=(5)²-4(√3)(-2√3)
=25+24
=49
As D<0,the given equation has real and distinct roots
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