Question

For 40 points,

In the quadratic equation kx^2 -6x-1 =0, determine the values of k for which the equation does not have any real root.

Answer 1

Answer:

k is any real number less than -9

Step-by-step explanation:

Concept:

If the roots of the quadratic equation

$ax^2+bx+c=0$ are not real, then $b^2-4ac<0$

Given equation is $kx^2-6x-1=0$

Here, a=k, b=-6, c=-1

since the roots of the equation are not real,

$b^2-4ac<0\\\\(-6)^2-4(k)(-1)<0$

36+4k<0

4k<-36

k<-9

Answer 2

Answer:

k is a number that less than -9

hope its helpful

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