Question

For 50 gm of hydrogen 24 ×10^23 molecules are removed . Find out the no. of moles of hydrogen....​

Answer 1

Given:

For 50 gm of hydrogen 24 ×10^23 molecules are removed.

To find:

The no. of moles of hydrogen

Solution:

Finding the no. of molecules present in 50 gms of Hydrogen:

The mass of Hydrogen = 50 g

The molecular mass of Hydrogen = 2 g/mol

∴ The number of moles of H₂, n = $\frac{50}{2} = 25$

We know,

$\boxed{\bold{No.\: of \:molecules = n \times N_A }}$

Therefore,

The number of molecules in 50 gms of Hydrogen is,

= (number of moles of H₂) × 6.023 × 10²³

= 25 × 6.023 × 10²³

= 150.575 × 10²³

Finding the no. of moles of Hydrogen left:

It is given that,

24 × 10²³ molecules are removed from 150.575 × 10²³ molecules of H₂.

∴ The remaining number of molecules is,

= (150.575 - 24) × 10²³

= 126.575 × 10²³

Now,

The no. of moles left is,

= $\frac{Remaining \:molecules}{6.023 \times 10^2^3}$

= $\frac{126.575 \times 10^2^3}{6.023 \times 10^2^3}$

= $\frac{126.575}{6.023 }$

≈ $\bold{21}$

Thus, 21 moles of Hydrogen are left.

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Answer 2

Step-by-step explanation:

so here is my short method hope u like it;)