For 50 ml of 60% acetone how much water is needed
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Percent volume of miscible liquids is calculated using the following formula:
% volume = volume of solute / volume of solution × 100%
The solute in this case is the acetone ( as it is being dissolved in the water)
Volume of solute = 5ml
The volume of the solution is given by the combined volume of the acetone and water = 50 ml
Therefore the % volume =
5ml / 50ml × 100% = 5 × 2 = 10%
Therefore the volume % of the acetone = 10%
Therefore
Given :
Volume of Solute =5ml
Volume of Solution=50ml
Volume By Volume Percentage = [Volume of Solute/ Volume of solution] x 100
=[5/50]x100
=[1/10]x100
=10%
∴Volume percentage of solution is 10%
Read more on Brainly.in - https://brainly.in/question/1536127#readmore
% volume = volume of solute / volume of solution × 100%
The solute in this case is the acetone ( as it is being dissolved in the water)
Volume of solute = 5ml
The volume of the solution is given by the combined volume of the acetone and water = 50 ml
Therefore the % volume =
5ml / 50ml × 100% = 5 × 2 = 10%
Therefore the volume % of the acetone = 10%
Therefore
Given :
Volume of Solute =5ml
Volume of Solution=50ml
Volume By Volume Percentage = [Volume of Solute/ Volume of solution] x 100
=[5/50]x100
=[1/10]x100
=10%
∴Volume percentage of solution is 10%
Read more on Brainly.in - https://brainly.in/question/1536127#readmore
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