For 50 points
find minor sector and major sector of a circle of radius 21 cm and the angle subtended at the centre of a circle is 60 degree
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We will just apply the formula,
Area of minor sector : πr²(center angle /360)
=22/7×21×21×60/360=66×21×1/6=231cm²
Similarly area of major sector = πr²(center angle/360)
=22/7 ×21 × 21 × 300/360=66×21×5/6=231×5=1155cm².
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Answer:
Area of major sector = 1155 cm^2 and minor sector = 231 cm^ 2
Explanation:
Please refer to the picture attached!
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