Question

For a 0.040 M ammonia solution : Calculate the PH and POH

Answer 1

Answer:

the pH of solution is 1.398

Solution and Explanation:

converting 0.040 into exponential form,

= 4 x 10⁻²

    pH = [H+]

pH = -log [ 4 x 10⁻²]

          = - [log 4 + log 10⁻²]

          = - [0.602 + (-2)]

         = - [ 0.602 - 2]

         =  - [-1.398]

        =     1.398